![]() Check this interactive example, which is more intuitive. Simply do an ls command, to get the list and use it as your test example text in there. I know my way around regex, but if you need to try before making changes, use an online tool to simulate the replacements. Then " (. )" captures all the remaining characters, in capture group 2. The pattern " (\d_)" captures six digits followed by two underscores, in group 1 (a parenthesis creates a capture group in regex). I wrote the regular expression that separates the two areas of interest in the filename. Each file came with a preceding id number, different on each sample. I downloaded this sound pack from pjcohen user in. Later I discovered that I can have the same results I needed by just using rename command alone. I don't know my way around combining commands in Linux very well, but an answer to this stack overflow question offered the perfect solution. I still recommend doing a backup anyway, just in case. In that way you can make sure that the expression works like you expected. The -n flag will make the command tell you the changes, but not actually change anything. One important advice, if you don't want to mess up your files, is to use the -n flag before actually doing the renaming. Rename 's/(regex pattern)/(replace pattern)/' * For security against your own mistakes, I advice you to do these changes only in folders that do not contain other folders, and keep a copy of the files without renaming safe somewhere else. Regular expressions can be a bit daunting at the beginning, but thanks to online tools such as, you can try out how the expression works before touching the filenames. I usually create a regular expression that separates the name into sections of interest. How to useĬombining Linux shell's find and rename commands, it is possible to use a regular expression to rename the files intelligently. Other possible use, is to homogenize certain text sections across all the files. One example is removing a section of the filename that makes the names unnecessarily long. I also give some insight on how to make this task a bit more intuitive. ![]() With this method you can rename files that match a description, match the sections that compose the filename and selectively remove, replace or append to each one of these sections. I wrote this guide mostly as a code snippet for myself to come back to. It is, however, hard to find some free tool to do this, and often these tools are paid or have nonsense limitations. Rewriting the contents of the files one by one, is the kind of nonesense one is supposed to get rid of when using a computer. ![]() Parser.Very often I find myself in the need to rename a batch of files, usually to remove, replace or to add content on a certain part of that filenames. Help='Write changes to files (otherwise just simulate the operation)', Parser.add_argument('-w', '-write-changes', Help='Top folder for the replacement operation', Parser = argparse.ArgumentParser(description='Recursive file name renaming with regex support') # (assuming two digits at the beginning and a 3 character extension # rename "12-lovely-spam.txt" to "lovely-spam-12.txt" Share Improve this answer Follow edited at 7:35 answered at 14:16 pLumo 21. inp, should be faster because no regex needs to be evaluated.) Remove the -n if you're happy with the output. \1, \2 etc) are supported too: # rename "spam.txt" to "spam-spam-spam.py" You can use perl-rename tool: rename -n 's//.inp/' 0-9 0-9 (or alternatively, use '. # only replace 'foo' at the beginning of the filename Simplest usage: # replace all occurences of 'foo' with 'bar' ![]() Use -w to actually write changes when you are satisfied with the dry run result, -s to suppress displaying non-matching files -h or -help will show usage notes. My take on a friendly recursive regex file name renamer which by default only emulates the replacement and shows what the resulting file names would be.
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